If it's not what You are looking for type in the equation solver your own equation and let us solve it.
15m^2+29m+12=0
a = 15; b = 29; c = +12;
Δ = b2-4ac
Δ = 292-4·15·12
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{121}=11$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(29)-11}{2*15}=\frac{-40}{30} =-1+1/3 $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(29)+11}{2*15}=\frac{-18}{30} =-3/5 $
| 1/8x+9=13 | | 34=6(v+7)-8v | | x-1/2-2x+1/3=-5/6 | | -6(9x+5)3x+4x=-408-x | | 3x-8+4x=20 | | 28=10+8+c | | x+32+5=2x | | 2x=−50 | | 4/5x+2/3+1/3x=x | | -38=-8y | | 30+0.05n=40 | | 10/20=x+2/x+6 | | 4y-y=2y | | 4x+3=2-6x | | 4.5+2.25x=100 | | 2(4x-11)=5x-7 | | 2r−7=r | | -6n−10=-n | | -9f=-10f−3 | | 9y=7+8y | | 65=x+10 | | -g=-3−2g | | -56y=8 | | -3b=8−2b | | 23=2x+1 | | 2^x-2=100 | | 4(2x-3)=0.2 | | 6v=7v−10 | | 5x-8/x^2=0 | | 6u=5u+10 | | 2^x-2=102 | | 3(5x+4)+3(2x+5)+2=21x+29 |